(z+3)(z^2-3z-4)=0

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Solution for (z+3)(z^2-3z-4)=0 equation: 


Simplifying
(z + 3)(z2 + -3z + -4) = 0

Reorder the terms:
(3 + z)(z2 + -3z + -4) = 0

Reorder the terms:
(3 + z)(-4 + -3z + z2) = 0

Multiply (3 + z) * (-4 + -3z + z2)
(3(-4 + -3z + z2) + z(-4 + -3z + z2)) = 0
((-4 * 3 + -3z * 3 + z2 * 3) + z(-4 + -3z + z2)) = 0
((-12 + -9z + 3z2) + z(-4 + -3z + z2)) = 0
(-12 + -9z + 3z2 + (-4 * z + -3z * z + z2 * z)) = 0
(-12 + -9z + 3z2 + (-4z + -3z2 + z3)) = 0

Reorder the terms:
(-12 + -9z + -4z + 3z2 + -3z2 + z3) = 0

Combine like terms: -9z + -4z = -13z
(-12 + -13z + 3z2 + -3z2 + z3) = 0

Combine like terms: 3z2 + -3z2 = 0
(-12 + -13z + 0 + z3) = 0
(-12 + -13z + z3) = 0

Solving
-12 + -13z + z3 = 0

Solving for variable 'z'.

The solution to this equation could not be determined.

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